| I just did the second one..
24) it says for all x, so substitute the x for 1 and 0 respectively
when you substitute x for 1:
9+k+36=3+n^2
42+k=n^2
k-n^2=42
when you substitute x for 0:
36=n^2
n=6
and now you substitute the second equation for first
k-n^2=42
k-6^2=42
k+36=42
k=6
k-n=?
6-6=0
Last edited by iwantfood; 07-10-2005 at 07:26 PM.
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