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TheMathProf · 05-09-2008, 03:06 PM

Oooh, good catch, Hannah.ng.

So used to seeing an initial condition with x = 0.

So that would change the solution above to 1 - sqrt(e)*e^(-1/x), and the limit to 1 - sqrt(e).

05-09-2008, 03:06 PM	#15
TheMathProf Member Join Date: May 2007 Threads: 0 Posts: 412	Oooh, good catch, Hannah.ng. So used to seeing an initial condition with x = 0. So that would change the solution above to 1 - sqrt(e)e^(-1/x), and the limit to 1 - sqrt(e). Last edited by TheMathProf : 05-09-2008 at 03:07 PM. Reason: Post now makes reference to poster being responded to, somebody else snuck in before my reply did. :)*