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Old 05-09-2008, 03:44 PM   #21
wendyling
Junior Member
 
Join Date: Apr 2006
Threads: 16
Posts: 247
for 5b this is what i did:
ln ly-1l = -1/x + k
e^(lnly-1l) = e^(-1/x) times e^(k)
let C = e^(k)
ly-1l = C(e^(-1/x))
then l0-1l=C(e^(-1/2)
so C = e^(1/2)
so y = e^(-1/x) times e^(1/2) + 1= e^(.5 - 1/x) +1

then for 5c: you'd get lim x-> inf. of the above
so e^(-1/infinity) equals 0 so the limit would be e^(.5 - 0) equal e^(.5)
and therefore the final answer is e^(.5) +1 or = sqrt(e) + 1
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