College Discussion - View Single Post

seanbow · 05-09-2008, 05:05 PM

The trapezoid question was 2b, and the intervals were unequal. This is how I did it, I dunno if it's right:

.5[(L(0)+L(1)) + 2(L(1)+L(3)) + (L(3)+L(4))]

=

.5(120+156) + (156+176) + .5(176+126)

=

621

Divide by 4 to get the average = 155.25

05-09-2008, 05:05 PM	#49
seanbow Junior Member Join Date: Aug 2007 Posts: 74	The trapezoid question was 2b, and the intervals were unequal. This is how I did it, I dunno if it's right: .5[(L(0)+L(1)) + 2(L(1)+L(3)) + (L(3)+L(4))] = .5(120+156) + (156+176) + .5(176+126) = 621 Divide by 4 to get the average = 155.25