| and (one more question lol).. on the one with the lake, it gave the area of the surface of the lake represented by area bounded by sin(pi*x) and x^3 - 4x (thus making A = sin(pi*x) - (x^3 - 4x))... and it gave the depth of the water to be represented by h(x) = 3 - x
that just looked like a cross-sectional problem to me.. it said find the volume, so i just set it up like a cross-sectional problem made up of rectangles perpendicular to the x-axis
so, my equation was [integral from 0 to 2 of (3 - x)(sin(pi*x) - (x^3 - 4x)) dx], where 3-x = h.. and sin(pi*x) - (x^3 - 4x) = b
that was right, wasn't it? |