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Zachsta · 05-09-2008, 10:18 PM

Wait, for 2(a), I did f(8) - f(3) / (8-3), since 5.5 is the median of those two numbers and not of 4 and 7

I thought you could only use equidistant numbers?

05-09-2008, 10:18 PM	#63
Zachsta Member Join Date: May 2005 Posts: 944	Wait, for 2(a), I did f(8) - f(3) / (8-3), since 5.5 is the median of those two numbers and not of 4 and 7 I thought you could only use equidistant numbers?