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tanman · 08-02-2005, 12:39 PM

Whoops.. too early in the morning to be doing SAT problems

Here's a new (hopefully correct) explanation:

0 = p^2-4 => p = 2 or -2 => point A = (0,2) or (0,-2)
5 = t^2-4 => t= 3 or -3 => poing B = (5.3) or (5,-3)

Like gcf101 said, instead of calculating all the slopes, it would probably be easier to plot the four points and look for the pair with the highest (steepest) slope.

08-02-2005, 12:39 PM	#5
tanman Senior Member Join Date: Aug 2004 Location: Student @ JHU (Baltimore, MD) / Houston, TX Threads: 26 Posts: 2,144	Whoops.. too early in the morning to be doing SAT problems Here's a new (hopefully correct) explanation: 0 = p^2-4 => p = 2 or -2 => point A = (0,2) or (0,-2) 5 = t^2-4 => t= 3 or -3 => poing B = (5.3) or (5,-3) Like gcf101 said, instead of calculating all the slopes, it would probably be easier to plot the four points and look for the pair with the highest (steepest) slope. Last edited by tanman : 08-02-2005 at 12:49 PM.