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tanman · 08-04-2005, 03:12 PM

The max area is when the given sides are the perpendicular sides of a right triangle (because you can never have another height > 7) so max area = (1/2)(6)(7) = 21.

Edit: I just googled the problem and found a solution on Dr. Math

08-04-2005, 03:12 PM	#2
tanman Senior Member Join Date: Aug 2004 Location: Student @ JHU (Baltimore, MD) / Houston, TX Posts: 2,147	The max area is when the given sides are the perpendicular sides of a right triangle (because you can never have another height > 7) so max area = (1/2)(6)(7) = 21. Edit: I just googled the problem and found a solution on Dr. Math Last edited by tanman; 08-04-2005 at 03:21 PM.