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Old 08-17-2005, 02:12 PM   #4
tkm256
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Join Date: Jul 2005
Location: Bloomington IN
Threads: 64
Posts: 1,533
17) The graph of x=y^2-4 is a sideways hyperbola. To find the "p" of for x=0, just plug it in:

0=y^2-4
4=y^2, y=2 or -2

Likewise, 5=y^2-4, 9=y^2, y=3 or -3

You know the hyperbola connects between (0,2) and (5,3) and between (0,-2) and (5,-3). Looking at a graph, the steepest line is between (0,-2) and (5,3).

The slope of that is: (-2-3)/(0-5)=-5/-5=1
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