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Old 09-01-2005, 09:39 AM   #2
optimizerdad
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Join Date: Aug 2004
Location: Chicago
Posts: 569
1. Use s = ut + (0.5)(a)t^2 where s=distance, u=init.velocity, a=accel

The pot travels a distance of L_w from the top ->bottom of your window, and takes t seconds to do it; so
L_w = ut + (0.5)gt^2, from which
u = (L_w - 0.5gt^2)/t

The pot was travelling at a velocity of u at the top of your window, and started at zero velocity when it was (h - Lw) length units from the *top* of your window. Suppose it took y time units to reach the top of your window. Now use
final_velocity = init_velocity + (accel)(time)
or u = 0 + gy
or y = u/g

Now use the distance formula
h - L_w = (0)(y) + (0.5)(g)y^2
or h = L_w + (0.5)(g)(u/g)^2
= L_w + ((0.5)/g)* ((L_w - 0.5gt^2)/t)^2
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