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Old 11-12-2005, 06:18 PM   #29
setzwxman
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Join Date: Aug 2004
Location: Pittsburgh Metro, PA
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page 427, #15.

We know that x = -3 at point P and x = 3 at Q (b/c PQ = 6, and can be divided into 3 on each side b/c parabolas are symmetric, and y = x^2 specifically is symmetric about the y-axis).

Plug in to y = x^2 to find the y value. y = 3^2 = 9.

Now plug into the other equation, with y = 9 and x = 3...

9 = a - (3)^2
9 = a - 9
18 = a
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