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RandomHSer · 06-29-2012, 12:20 PM

Just plug in x=2 for the equation,
giving f(2)=-3=g(2)^2-2g(2)-2
adding 3 to both sides gives g(2)^2-2g(2)+1=0
factoring: (g(2)-1)^2=0, g(2)=1

06-29-2012, 12:20 PM	#2
RandomHSer Junior Member Join Date: Jun 2012 Posts: 121	Just plug in x=2 for the equation, giving f(2)=-3=g(2)^2-2g(2)-2 adding 3 to both sides gives g(2)^2-2g(2)+1=0 factoring: (g(2)-1)^2=0, g(2)=1
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