College Discussion - View Single Post - Consolidated List of Solutions to Blue Book Math Problems

setzwxman · 11-28-2005, 06:14 PM

p. 488, #4

You'll be using a box of 12, a box of 6, and 3 individually-priced donuts to get the lowest possible cost of 21 donuts. So...3.59 + 1.89 + 3(0.40) = 6.68, (B)

11-28-2005, 06:14 PM	#39
setzwxman Member Join Date: Aug 2004 Location: Pittsburgh Metro, PA Threads: 12 Posts: 344	p. 488, #4 You'll be using a box of 12, a box of 6, and 3 individually-priced donuts to get the lowest possible cost of 21 donuts. So...3.59 + 1.89 + 3(0.40) = 6.68, (B)