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Old 04-13-2006, 10:50 PM   #7
Evilbooyaa
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Join Date: Feb 2006
Location: Pittsburgh
Threads: 11
Posts: 656
stan thanks for bringing my question to this thread, but unfortunately your answer is incorrect (you can't use HCl or NaOH, but something else is there if that's a hint for ya)

the first one is KCN - CN- + H2O <--> HCN + OH-

2nd one- PV = nRT T = 273, P = 1, V = 11.2
n = 11.2/ (.0821*273)
n = .5 mol.
22g/.5mol = 44g MM = CO2.

stan for yours, I actually have no idea. wow, nice question.

you know me- damn redox..... gotta do this out on paper.
Mg + NO3- --> Mg+2 + NH4+
breaks down into
Mg --> Mg+2 and NO3- --> NH4+
Mg --> Mg+2 + 2e- = 4Mg --> 4Mg+2 + 8e-
NO3- + 10H+ + 8e- --> NH4+ + 3H2O

combine the two, the 8e- cancel
4Mg + NO3- + 10H+ --> NH4+ + 3H2O + 4Mg+2

coefficient for H+ is 10 assuming the solution is acidic.
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