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Originally Posted by Student Question 3
a. Both are first-order.
b. Rate = k[I-][ClO-]
k = 6.1 x 10^2 L mol^-1 s^-1
c. ln[H2O2]
mol L^-1 min^-1
Uncatalyzed graph begins at (0.0 min, 1.00 mol L^-1) and has a less negative slope. |
I agree except for the units in (c). The units would just be minutes^-1, since the rxn is first order, rate = k[H2O2].