Major error in Barron's Math II 8th edition:
Page 123, part B of example #1:
(4x^2) + (4y^2) - 12x - 20y - 2 = 0
You're supposed to complete the square to find the equation of the circle and here's how they do it:
(x^2 - 3x + 9/4) + (y^2 - 5y + 25/4) - 2/4 = 9/4 + 25/4
(*note the 2/4*)
( x - 3/2)^2 + ( y - 5/2)^2 = 9
My question is: shouldn't the costant '2' of the original equation be carried out the other side of the equal sign which would change the answer completely? And why is it 2/4 instead of just 2?
...or is this just another of Barron's typos??