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04-15-2006, 11:31 AM
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#31 | | | I also have this question
Consider the multi-step reaction that has the overall reaction
2A + 2B ---- C + D
What is the rate law expression that would correspond to the following proposed mechanism?
A + B <-------> I (fast)
I + B -------> C + X (slow)
X + A --- D (fast)
1. Rate = k [b]
2. Rate = k [A]2[b]2
3. Rate = k [A]
4. Rate = k [A]2[b]
5. rate = k [i][b]
6. Rate = k [A]2
7. Rate = k [A][i][b]
8. Rate = k [A][b]2
9. Rate = k[A][b] | |
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04-15-2006, 01:04 PM
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#32 | | Junior Member
Join Date: Dec 2005
Threads: 21
Posts: 142
| smder,
G=RTlnK
-33320=8.31(273)lnK, solve for K
of the three scenarios, only increase in temp changes the Kp (decrease Kp since exothermic). however, i have no idea how to solve for the new Kp. help?
quizquick, answer is 5
What is the most massive subatomic particle? |
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04-15-2006, 01:15 PM
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#33 | | Junior Member
Join Date: Aug 2005
Threads: 25
Posts: 276
| I think the answer to QuizQuick is 8.
The slow step is the rate-determining so:
rate = k [i][b]
But the first equation is equilibrium so:
Keq = [i] / [A][b]
[i] = Keq [A] [b]
rate = k Keq [A][b] [b]
and since k*Keq just yields another k.
rate = k [A][b]2, or 8.
Let me know if I did something wrong. |
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04-15-2006, 01:21 PM
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#34 | | | Yeah I guess both could work. At first I did put 5, but then I noticed that there wasn't a 5 in the original reaction...so maybe it's 8. I dunno. | |
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04-15-2006, 01:29 PM
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#35 | | | Another one is:
For the elementary reaction
CO + O2 ----> CO2 + O
which of the following is correct (in the order: with respect to CO, overall order, units of rate constant)?
1) 1;2; M^-1 s^-1
2) 1;1; M^-1 s^-1
3) 2;0; M^-1 s^-1
4) 1;1;s^-1
5) 0;1;s^-1
I put 1, is that right? | |
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04-15-2006, 01:30 PM
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#36 | | Member
Join Date: Feb 2006
Threads: 119
Posts: 779
| neutron
stanfordream...if im not mistaken..this is how u would find the new Keq at 40C
(btw..in the original problem i meant to write standard state, not STP)
dG= -RT ln Keq
dG= dH - TdS
dH - TdS = -RT ln Keq
-DH/RT - DS/R = ln Keq
now u would find the dH and dS values for the rxn, plug those in, along with R and the new temperature and find Keq at 40C!!!!! |
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04-15-2006, 01:38 PM
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#37 | | Junior Member
Join Date: Aug 2005
Threads: 25
Posts: 276
| Another one is:
For the elementary reaction
CO + O2 ----> CO2 + O
Since its an elementary reaction, there are no steps/no mechanism. Hence, the [ ] of each reactant is raised to its coefficient.
rate = k [CO] [O2]
Then, to find the units of k. Think of it logically.
rate must be in units of M/s. Both the [ ] have units of M, so M^2. Hence, units of k must be M^-1 s^-1.
1) 1;2; M^-1 s^-1
2) 1;1; M^-1 s^-1
3) 2;0; M^-1 s^-1
4) 1;1;s^-1
5) 0;1;s^-1
My answer would be 2.
Please, someone correct me if I am wrong. |
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04-15-2006, 01:45 PM
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#38 | | Junior Member
Join Date: Dec 2005
Threads: 21
Posts: 142
| yeah the rate law is 8. i went by it too quickly and didnt see twas a rate mechanism.
smder, ok i see. i didnt know i could look up dH and dS, so i thought there was another way to do it.
regarding my question, the most massive subatomic particle is actually an alpha particle.
how do real gases deviate from ideal gases? |
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04-15-2006, 01:46 PM
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#39 | | Junior Member
Join Date: Dec 2005
Threads: 21
Posts: 142
| for the elementary rate reaction question, the overall order is 2. so quizquick was right. |
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04-15-2006, 02:10 PM
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#40 | | Junior Member
Join Date: Aug 2005
Threads: 25
Posts: 276
| ^ Oh right. That was really stupid of me to read the question wrong...
Real gases deviate from ideal gases because they have intermolecular attractions.
Q: What is a lanthanide contraction? |
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04-15-2006, 03:14 PM
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#41 | | | lanthanide contraction is when the ion radii of the lanthanides is decreasing from 1.061 Ångström La3+ to 0.848 Ångström Lu3+ in the lanthanide period | |
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04-15-2006, 03:16 PM
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#42 | | | Q
For the multiple step reaction mechanism
Slow NO + Br2 ---> NOBr2
Fast NOBr2 + NO ----> 2 NOBr
Net 2 No + Br2 ----> 2 NOBr
What would be the correct rate law? | |
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04-15-2006, 04:31 PM
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#43 | | Member
Join Date: Apr 2006 Location: University of Pennsylvania 2011
Threads: 32
Posts: 825
| For the multiple step reaction mechanism
Slow NO + Br2 ---> NOBr2
Fast NOBr2 + NO ----> 2 NOBr
Net 2 No + Br2 ----> 2 NOBr
What would be the correct rate law?
I am just guessing but here goes. The slow reaction determins the rate so:
Rate=k[NO][Br]
My question:
What is the difference between alkenes, alkanes, and alkynes?
Good Luck!! |
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04-15-2006, 04:50 PM
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#44 | | | Alkanes have single bonds, alkenes have double bonds, and alkynes have triple bonds.
My q.
When color is Ag2CrO4? | |
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04-15-2006, 06:03 PM
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#45 | | Junior Member
Join Date: Dec 2005
Threads: 21
Posts: 142
| no idea, but i'm guessing white?
list the following from the least reactive to the most reactive:
Na, Ca, Mg, K, Cs, Zn |
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