| stanfordream- HC2H3O2 is actually a solution (like NaOH), but i'll go with a powder I suppose..... maybe it is. never seen HC2H3O2 powder.
wait a second.
how do you make a buffer out of HC2H3O2 and NaOH?
you need NaC2H3O2 or something of the sort...... you need the acid and the anion/cation to produce a buffer..... you can't make it out of HC2H3O2 and NaOH...... can you?
help please!
Scareya- ill go thorugh the first one step by step
A)left- P=+3, Br=-1, O=-2 H=+1
right- H=+1, O=-2, P=+3, Br=-1
therefore, don't involve oxidation/reduction
2)'I' goes from a -1 to +5--> oxidation
'Cl' goes from +1(?) to -1--> reduction
3)'S' goes from +4 to +6--> oxidation
'N' goes from +5 to +2 --> reduction
4)'Br' goes from -1 to 0 --> oxidation
'S' goes from +6 to +4(in the S)2, which I assume to be SO2)--> reduction
stanfordream's question is still on the board, so I won't post a new one.
btw, sristi, don't feel bad about posting questions! it helps those too lazy to look for questions themselves |