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sciencenerd
Registered User Posts: **1,479** Senior Member

What's the best way to study for Calculus BC? I've been going over the various chapters, but there's just so much to know.

Post edited by sciencenerd on

## Replies to: Best way to study for Calculus?

65Junior Member3,447Senior Member810Member354Member83Junior Member126Junior MemberAlso, the FRQ likes to ask similar things too. Almost surely there will be area between curves/solid of revolution question as the first question of the FRQ. Make sure to know that formula and know how to find points of intersection on your calculator. Also, the FRQ enjoys testing on concepts in calculus like if you integrate the rate of change in position (or velocity) you'll get the change in position (or displacement) Also make sure to be able to prove your statements. If you want to say that at x = 3, f(x) has a point of inflection, you must also write the reason this is is because f''(3) = 0, or f''(3) = undef.

Always be explicit, don't use pronouns. "It is increasing" is not good. Explaining "f(x) is increasing at 3<x<5 because f'(x) > 0" would probably get you some points, though.

600MemberYour best bet would be to do the FR's available online. However, questions about different series show up more on the MC so try to find some old tests. As intellec7 mentioned, you need to be able to explain your answer to the FR, which shouldn't be too hard since the calculations are rather simple. Reading the question is very important because a few words can make the difference in whether you need to integrate or differentiate in the problem.

810Memberconcavity, which means it is not enough for f "(x) = 0 or for f "(x) to be undefined. The key for a point of inflection is for the sign of f "(x) to change, either from positive to negative or from negative to positive.The reason why you look for f "(x) = 0 or f "(x) to be undefined is because these give you the locations of x-values where this sign change

couldoccur.For instance, the function f(x) = x^4 has f "(x) = 12x^2, so f "(x) = 0 at x = 0. However, f "(x) > 0 for all x except x = 0, and so there is no inflection point at x = 0.

The rest of the advice in the last two posts is spot on.

237Junior Member1,479Senior Member