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Old 05-06-2008, 03:17 PM   #16
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Quote:
right now, i also regret skipping calc AB to take BC. so unprepared.
they're separate classes? At my school, there's a AB or BC option. A friend of mine switched out of BC to AB and he's loving it. I wish I did that do haha.
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Old 05-06-2008, 04:43 PM   #17
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Aaargh... I have a choir rehearsal tonight so I can barely do ANY studying for this test now...

Oh well. I guess I'm as prepared as I ever will be.
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Old 05-06-2008, 04:44 PM   #18
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I'm taking AB at school and independently studying the BC material.. fun stuff :|
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Old 05-06-2008, 05:32 PM   #19
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The MC for BC seem to be harder than free response, at least for me. And there's tons of stupid FTC and 2ndFTC junk, and I don't like that. Not enough basic derivation and integration, lol. More find y' of y=e^x please.

On a serious note, our teacher had to rush through taylor/power series because we ran short of time, so... is that a really huge portion of the test? And can a basic understanding of the taylor series formula get you the majority of the taylor questions, or do you have to really understand their intricacies? Because I still don't understand them, and I don't know if its worth learning them at this point, since tecnically I should be able to get a four or five without being good at them.
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Old 05-06-2008, 05:39 PM   #20
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The MC for BC seem to be harder than free response, at least for me. And there's tons of stupid FTC and 2ndFTC junk, and I don't like that. Not enough basic derivation and integration, lol. More find y' of y=e^x please.
FTC? FTC is the easiest thing in the entire course. The FTC problems they ask just require you to plug values into a simple formula.

Quote:
On a serious note, our teacher had to rush through taylor/power series because we ran short of time, so... is that a really huge portion of the test? And can a basic understanding of the taylor series formula get you the majority of the taylor questions, or do you have to really understand their intricacies? Because I still don't understand them, and I don't know if its worth learning them at this point, since tecnically I should be able to get a four or five without being good at them.
Sequences and series are hard, imo. There is always a free response question on them and students do very poorly on it. There are always 1 or 2 MC questions on interval of convergence, 2-3 on a taylor of maclaurin series and another on the lagrange error bound.
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Old 05-06-2008, 05:50 PM   #21
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Yeah, my teacher barely taught series and sequences, and I realized trying to teach it to myself now is impossible.
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Old 05-06-2008, 05:52 PM   #22
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I don't know a lot about series, but I can usually figure out most of the problems involving them (that I've encountered, anyway). Taylor series are a ***** though.
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Old 05-06-2008, 05:58 PM   #23
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Use the formula for the Taylor Series. Don't overthink it.
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Old 05-06-2008, 06:01 PM   #24
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Nick and Hippo and Tweetjazz, I would memorize the Taylor series and the general term for sin(x), cos(x), ln(x+1), and e^(x). You may be able to derive them but it is much much MUCH easier to memorize the formula. It also saves you a lot of time.

The way I remember sin(x) and cos(x) is somewhat interesting and I'll share but bare with me.

on the unit circle cos=x right? well, to make an X you need two lines. Two is even so the powers of the maclaurin series for cos(x) are even. and let's pretend that 0 is also even.

so, cos(x)=1 - (x^2)/2! + (x^4)/4! - (x^6)/6! + ....

b/c x^0=1


on the unit circle, sin=Y and to make a capital Y, you need three lines. three is odd so the powers for sin are odd.

sin(x)= x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ....


you always divide by the factorial of the power and the series alternate. I thought it was clever but my calculus teacher didn't get it. Hope it helps someone else!


e^x is always simple. it's just all the powers/ the power factorial. you start at 0 and keep going.

so...

e^x= 1 + x +(x^2)/2! + (x^3)/3! + (x^4)/4! + .....


ln(x + 1) may trip you up because there are no factorials in it. The way I think of it is that ln(x+1) has a +1 attached to the X so it's a tricky ricky type situation. So, ln(x+1) is also a tricky ricky situation because it doesn't have the factorials AND it starts at X because X is sexy AND it alternates. (laugh all you want, but I remember these things. )

so,
ln(x + 1) = x - (x^2)/2 + (x^3)/3 - (x^4)/4 + .......


so enjoy. and i hoped you at least got a laugh (if my awesome mind trick didn't help you.)



PS Is it bad that I haven't started studying yet?
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Old 05-06-2008, 06:15 PM   #25
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Yeah, taylor and power series are a b****
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Old 05-06-2008, 06:42 PM   #26
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quick question
why is the derivative of 2e^x
still 2e^x

i guess im having a brainfart but sohuldn't it be just e^x... im dumb
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Old 05-06-2008, 06:44 PM   #27
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because the derivative of e^x is always e^x
you keep the constant when you take the derivative
hence the derivative of 2x is 2


?
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Old 05-06-2008, 06:48 PM   #28
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right >< thanks
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Old 05-06-2008, 07:23 PM   #29
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for sin/cos taylor series .. you could also just memorize the sin series and do the derivative of it to get the cos taylor series (for both individual terms and the general term)
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Old 05-06-2008, 07:34 PM   #30
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Nice idea, proud08er!
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