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AP Calculus BC Exam Thread. How are you preparing? AP Calculus BC Exam Thread. How are you preparing?
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Old 05-06-2008, 07:40 PM   #31
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I took the AP stats exam today and it was hard. If the Calc BC test is supposed to be harder, then I'm scared!!! I get everything, but the questions are gonna be hard cus AP just makes it confusing! The only subject I'm a little shaky on is the lagrange error bound and the volumes of things by using cross-sections so I'm going to review those now and take a practice test. The exam is tomorrow morning !!! I hate morning tests!!
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Old 05-06-2008, 07:52 PM   #32
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What percent do you need to get right on BC for a 5?
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Old 05-06-2008, 07:56 PM   #33
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im winging it =D
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Old 05-06-2008, 08:24 PM   #34
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bump my questions 2 up if anyone knows?
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Old 05-06-2008, 08:33 PM   #35
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You have to get roughly 60% of the total composite score.
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Old 05-06-2008, 08:39 PM   #36
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I'm not. :]
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Old 05-06-2008, 08:50 PM   #37
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thanks crn
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Old 05-06-2008, 09:22 PM   #38
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Do we have to know work? Our teacher said no, but my barrons review has the work problems like when a barrell of oil is being emptied over the top and springs being springed and stuff. But then barrons overdoes it I have heard, so work or no work?
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Old 05-06-2008, 09:25 PM   #39
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I think its fair game for the MC, its just force times distance, although the distance part can get a little tricky when you're integrating...what about Lagrange, we didn't really cover it but I'm guessing there might be a MC about it.
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Old 05-06-2008, 09:51 PM   #40
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My teacher told us that LaGrange is such a miniscule part of the test if its even on there that it won't matter so she didn't teach it.
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Old 05-06-2008, 10:15 PM   #41
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i hope bc isnt gonna be killer hard
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Old 05-06-2008, 10:25 PM   #42
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boredpirate:

its almost always on the series question...Has your teacher seen the last 5+ years of FR?
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Old 05-06-2008, 10:26 PM   #43
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i'm screwed for convergence
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Old 05-06-2008, 10:36 PM   #44
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I have a question I need help with!

If n is a positive integer, then limit as n approaches positive infinity of

1/n * [sin(pi/n)+sin(2*pi/n)+. . . + sin (n*pi/n)] is?

The answer is 2*pi, but I have no idea how to get that.
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Old 05-06-2008, 10:42 PM   #45
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Can you give some more terms in the middle of that series? Does it just start from 1 and go to n? If so, then why did you write sin(pi/n) rather than sin(pi)?

EDIT: Also lim n->infinity (1/n)=0 and since the limit of products is the product of the individual limits, the answer should be zero since its 0* (whatever the lim n->infinity of [sin(pi/n)+sin(2*pi/n)+. . . + sin (n*pi/n)] is).
Last edited by afruff23; 05-06-2008 at 10:47 PM.
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