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05-09-2008, 11:02 AM
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#16 | | Senior Member
Join Date: Mar 2008 Location: Arizona
Posts: 1,186
| I'm certain I would have gotten a five on AB, but I decided to chance BC. Bad idea it seems now, there were a lot of series in there that I didn't know how to do :/
Oh well, a 4 is still good for admissions right (homeschooled)? And I'll retake next year for the credit. | 
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05-09-2008, 11:08 AM
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#17 | | Junior Member
Join Date: Sep 2006
Posts: 98
| I believe so, yes. A 4 is enough to grant credit at many colleges too, so that's a plus  | |
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05-09-2008, 11:51 AM
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#18 | | Junior Member
Join Date: May 2007
Posts: 119
| I got answers similar to stix's and also got
(2,3) because it was (-oo,3) u (2,oo)
For the range one on the logistic curve, I put (6,8) but I also whimped out and put (0,6) and I said something about if the points on the solution are above y=6 then it is (6,8), but if they're below it is (0,6). Is this incorrect? | |
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05-09-2008, 11:55 AM
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#19 | | Member
Join Date: Dec 2007
Posts: 367
| ^5b has to be never....how is it 2,3...f'(x)<0 and f''(x)>0, are never met simaltaneousy in any one given interval so.... | |
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05-09-2008, 12:22 PM
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#20 | | Junior Member
Join Date: May 2007
Posts: 119
| I can be wrong, but when I did my inequalities I got that one was met for (-oo,3) and the other from (2,oo) and the cross section of that is (2,3) | |
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05-09-2008, 12:23 PM
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#21 | | Senior Member
Join Date: Mar 2008 Location: Arizona
Posts: 1,186
| Hmmm, now I'm not sure lol | |
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05-09-2008, 12:33 PM
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#22 | | Member
Join Date: May 2007
Posts: 428
| (2,3) is the correct interval for 5(b). | |
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05-09-2008, 12:34 PM
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#23 | | Member
Join Date: May 2007
Posts: 428
| intellec7, the initial condition of (0,8) helps you to determine which one of those solutions is correct.
Although since you already know y=8 is part of the range, it would have to be (6,8], rather than (6,8). | |
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05-09-2008, 01:30 PM
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#24 | | New Member
Join Date: Nov 2007 Location: Pittsburgh
Posts: 26
| you only need about a 65% to get a 5 on the AP exam | |
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05-09-2008, 02:12 PM
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#25 | | Junior Member
Join Date: Feb 2008
Posts: 211
| "^5b has to be never....how is it 2,3...f'(x)<0 and f''(x)>0, are never met simaltaneousy in any one given interval so...."
Yes they are, just take a look at 1/x on (0, oo) | |
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05-09-2008, 02:20 PM
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#26 | | Junior Member
Join Date: Feb 2008
Posts: 211
| And while we're on this topic, here's the work for that question: http://img512.imageshack.us/img512/7558/5bab4.png
Sorry for the messiness, writing with a mouse is pretty hard.
Anyways, you can see from the work that f'(x) is negative on (-oo, 3) and f''(x) is positive on (2, oo) | |
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05-09-2008, 02:35 PM
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#27 | | Member
Join Date: Dec 2007
Posts: 367
| ^ i had all that same work, but then I was being stupid, and I wrote that it never happens because it not in the same interval...do you think I'll get partial credit for the same work as you have above..(like maybe a 1 out of 2 points or something ? | |
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05-09-2008, 02:54 PM
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#28 | | Senior Member
Join Date: Aug 2005 Location: Ohio
Posts: 1,092
| On 3 (a) and 3 (b), I got 80+128(x-2) and 80+128(x-2)+488/6(x-2)^2+448/18(x-2)^3, and my answers were 67.8 and 68.677, did I mess up somewhere? | |
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05-09-2008, 02:59 PM
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#29 | | Member
Join Date: Dec 2007
Posts: 367
| ^you're probably fine dude , just a minor rounding thing that's all!!! | |
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05-09-2008, 03:10 PM
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#30 | | Member
Join Date: Dec 2007 Location: valley of the sun, AZ
Posts: 527
| How is 4b) 3 times? | |
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