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Old 05-10-2008, 09:15 PM   #91
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a 55 is a verrry safe 4.....
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Old 05-10-2008, 11:08 PM   #92
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ok, so i feel sort of stupid because it seems like this is a pretty easy problem...
but could anybody please explain how to do 6(c)? and 6(d)? i seriously have no idea how. i feel like i'm missing a really important concept.

also, 2(b)? you couldn't use the (b-a)/2h (y1+2y2...) etc. formula, right? then how do you do it?

thanks!!
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Old 05-11-2008, 12:56 AM   #93
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so anyone think i'll be penalized for accidentally answering the integral on 1b?

i should probably be considering i didn't read it properly :/

but they wouldn't void the whole question right?
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Old 05-11-2008, 12:58 AM   #94
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I don't believe so, Freezenthaw, but I suppose if the answer is wrong, they could in theory penalize you for it.

jersey_jazz, for 2(b), you can find the areas of each trapezoid individually, using the h(b-a)/2, where h varies for each value of h.

I haven't looked at 6, so I'll leave that one open.
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Old 05-11-2008, 01:04 AM   #95
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You probably won't be penalized for answering it. I don't get the point of those questions if they're on a calculator section, really...
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Old 05-11-2008, 01:16 AM   #96
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The reason has to do with the allocation of points. There are only 9 points available for the question, and usually, evaluating an integral is worth a point.

They must have thought that getting an answer for that integral would leave them with one point too many.
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Old 05-11-2008, 08:40 AM   #97
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not to be a pain
but isnt the area of a trapezoid
(1/2)(b+a)h
not (1/2)(b-a)h like the math prof
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Old 05-11-2008, 10:34 AM   #98
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That's what happens when I post at 11:16 PM. You're right.
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Old 05-11-2008, 04:23 PM   #99
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for part 3a, i got 67.2 and for part 3b, i got 67.98622222...

almost positive that these answers are right

first-degree series = 80 + 128(x-2)

third-degree series = 80 + 128(x-2) + 244/3(x-2)^2 + 224/9(x-2)^3
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Old 05-11-2008, 05:45 PM   #100
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^ crap i think i got those taylor series wrong
i wrote out the 1st and 3rd degree series correctly

but instead of adding 128(1.9-2) to 80, i must have left out the negative sign in the product of 128(-.1) so i ended up getting 92 instead of 68

=[
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Old 05-11-2008, 05:47 PM   #101
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Looking at these responses, in total I think I got around 4/6 or maybe a little bit better.
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Old 05-11-2008, 08:15 PM   #102
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anybody know how to do 6(c) and (d)??
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Old 05-11-2008, 09:08 PM   #103
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Oh right mathprof, that makes sense.
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Old 05-11-2008, 11:03 PM   #104
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how much would i be penalized if i wrote down interval 2-3 instead of (2,3)
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Old 05-11-2008, 11:27 PM   #105
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and 0-1 4-6

idk what happened i just blanked out
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