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I will be a junior next year and I am debating whether to take AB or BC calculus. This is my current schedule:
AP calculus AB or BC?
Honors Spanish III
AP english language and composition
Honors criminal law and justice
AP environmental science
At my school, both classes are year long. BC calculus covers both AB and BC, so I'm assuming it moves twice as fast as AB. My pre-cal teacher told me to take BC, although I'm a little hesitant. Math has always been the hardest subject for me. I have made A's in all my highschool math classes (geometry, algebra II, pre-cal), but I have had to work hard for them at times. I found geometry and trig to be much easier for me then alegbra II or the alegbra parts of pre-cal. One of my main questions is how much harder is BC than AB? Is there a lot more material covered in BC than in AB?
I am normally a person who wants to take the hardest classes and challenge myself as much as possible, but math is a subject where I'm not completely 100% confident because I have struggled a little in the past. I want to take BC because I know it will look better for college, but I also have a lot of other AP's next year, plus several extracurriculars. I don't want to stress myself out too much next year by tackling BC and finding out that it's too much for me to handle. Will it hurt my admissions to college if I take AB over BC, or will this not be all that important to colleges? Do I have a tough enough schedule as it is or should I try to push myself by taking BC?
Any advice is appreciated and thank you to anyone who read this whole thing!