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Old 07-22-2007, 10:57 PM   #1
Junior Member
 
Join Date: May 2006
Location: Canada
Posts: 140
Trig help

Hopefully there is someone around here who is better at math than I am (which, I admit, is not difficult to be, even in less intelligent circles).
I have two types of questions that I hope you can help me solve and maybe briefly explain why. This is not just to get answers out of you guys, because I have the answers in front of me. I just don't get why.

1) Determine the exact value of tan(5pi/6)
2) Solve: cscx + 2 = 0 (in radian mode)

I'm soo lost guys, please help...
Canucker is offline   Reply   
Old 07-22-2007, 11:07 PM   #2
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Join Date: Jun 2007
Location: OK
Posts: 726
1. You should just remember these stuff. Reference angle is pi/6, so it's either positive or negative sqrt(3)/3. In this case, angle is in 2nd quadrant, so answer is -sqrt(3)/3.

Another way you can do is is by: tan = sin/cos
sin(5pi/6) = 1/2
cos(5pi/6) = -sqrt(3)/2
sin/cos = -1/sqrt(3) = -sqrt(3)/3

2. move 2 to other side to get cscx = -2
take reciprocal of each side to get sinx = -1/2
now you know x = 7pi/6 or 11pi/6
if you want all solutions, then x = 7pi/6 + 2pik or 11pi/6 + 2pik where k is an integer.

Hope this helped.
jenkster is offline   Reply   
Old 07-23-2007, 12:13 AM   #3
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Join Date: Mar 2006
Location: University of Washington.
Posts: 2,820
yeah, you really have to know the unit circle.
andreaaaaaa is offline   Reply   
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