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Old 07-16-2007, 09:04 PM   #1
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Join Date: Jan 2007
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HASS-D Lottery algorithm

I was just wondering how I should select classes for the lottery thing for HASS-D. I have 1 class I want to take a lot more than the others(there are 6 slots/choices). Does anyone know if we will be more likely to get into our top choice if we fill up fewer slots, and leave more blank? Or what if we fill #1 leave #2, #3, #4 blank, and fill #5, and #6, what will that do?
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Old 07-16-2007, 09:34 PM   #2
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No, putting extra choices won't diminish your chances of getting your first choice -- the lottery isn't trying to maximize everybody's happiness or anything. All it does is try to put everybody in his or her first choice, and if you don't put a second choice and you don't get lotteried into your first choice, you won't get a HASS-D assignment.

Selecting 1, 5, and 6 would be the same as selecting 1, 2, and 3, and neither option will make it less likely that you'll be lotteried into 1. If there are a few courses you'd be willing to take, it's to your advantage to select all of them in the lottery.

I should probably note also that if you don't get your first-choice HASS-D, the odds are still good that you can take the class. You just have to show up on the first day of class with an add/drop form -- since a decent number of students who are lotteried in will end up deciding to take other classes, there are almost always enough spots for people who weren't lotteried in. (My fiance got through MIT without ever entering the HASS-D lottery. )
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Old 07-16-2007, 10:42 PM   #3
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ah, cool, thanks Mollie!
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Old 07-17-2007, 10:30 AM   #4
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o, and also, I came across this page about the algorithm, which says what Mollie just said :-) http://web.mit.edu/shass/undergradua...lgorithm.shtml
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