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Working2college
Posts: **115**Registered User Junior Member

I have forgotten how to do this. I recall the formula, but we went over it a week before the final so I was not paying 100% attention to learning it as I was to getting all the information I accumulated back and ready for the exams. something like

N(term)=N+1(something) and there are different ways to manipulate the formula, but I am guessing you only need basic sequence knowledge for the SAT. I am only concerned with getting a better SAT score right now.

In a certain sequence where the numbers are increasing, the difference between consecutive terms is always the same. If the fourth term in the sequence is 19 and the eleventh term is 47, what is the first term in the sequence?

(A) 1

(B) 3

(C) 7

(D) 8

(E) 11

won't give away answer so you guys have some fun without spoiling it

N(term)=N+1(something) and there are different ways to manipulate the formula, but I am guessing you only need basic sequence knowledge for the SAT. I am only concerned with getting a better SAT score right now.

In a certain sequence where the numbers are increasing, the difference between consecutive terms is always the same. If the fourth term in the sequence is 19 and the eleventh term is 47, what is the first term in the sequence?

(A) 1

(B) 3

(C) 7

(D) 8

(E) 11

won't give away answer so you guys have some fun without spoiling it

Post edited by Working2college on

## Replies to: Math question Help

115Registered User Junior Member(A) negative 5

(B) negative 1

(C) 1

(D) 2

(E) 5

another one for you..answer for first one later though

379Registered User Member115Registered User Junior MemberNote: Figure not drawn to scale.

The figure above shows a right circular cylindrical wheel of cheese 2 inches high from which a wedge weighing 1 over 2 pound has been cut. All cuts are perpendicular to the base and radiate from points B and C, the centers of the circular top and bottom. What is the weight, in pounds, of the original uncut wheel?

(A) 2

(B) 3

(C) 4

(D) 6

(E) 12

I'm sure some where there are these exact same questions.. I am doing an online skills insight on the collegeboard website.

but still

I do not understand this one either..guess i'm really rusty after the summer

the cut would be 30 degrees according to the figure not shown.. 30 out of 360 or 12% of the whole thing. But using 12% did not get the right answer for me so I am stuck

115Registered User Junior Memberby the way, if you want to make fun of how easy they are. maybe you should use the right words to say so. They are or they're not 'there'

115Registered User Junior Member(A) (0 comma 0)

(B) (1 comma 1)

(C) (1 comma 2)

(D) (1 comma negative 2)

(E) (2.5 comma 2.5)

these have plagued me quite frequently.. If anybody has a quick answer to this, It would be much appreciated. In honors algebra 2 we went over this extensively but I have forgotten the formula. Besides, there has to be a quick way to answer these sort of problems at least one will be on the sat itself

379Registered User Member379Registered User Member115Registered User Junior Memberthese are from the Skills Insight on the sat website, but without answer explanations to them

anybody with explanations is welcome to help out. Usually these type of questions tend to get answered quickly.

the first one is 7 and the other is 5 but how? I have seen some great explanations on this site and they always make other questions even easier. Help would be much appreciated

379Registered User Member379Registered User Member379Registered User Member379Registered User Member115Registered User Junior MemberI think the 4th on is B.

379Registered User Member115Registered User Junior MemberThe circumference, in inches, of a certain circle is C, where Absolute value (C minus 20.5) less than or equal to 0.5. Which of the following is a possible area of the circle, in square inches?

(A) 64 over pi

(B) 81 over pi

(C) 100 over pi

(D) 121 over pi

(E) 144 over pi

I did it this way, I figured that c= any number 20.5-21

c=2 pi R, so i divided by 2 pi the lowest and highest number to get a range of acceptable numbers

but I'm still sort of confused though, the correct answer is C 100/pi

guess i just needed to rethink it or something..i did not understand if what i did was right.

yea a refresher on how to do 4th one would be appreciated.