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obsessedAndre
Posts: **240**Registered User Junior Member

"Find x > 3 such that

ln(x) < x^(0.1)"

How do you solve this type of problem? I plugged it into my TI-89 solver and didn't get anything. As a hint, the number is unbelievably huge.

ln(x) < x^(0.1)"

How do you solve this type of problem? I plugged it into my TI-89 solver and didn't get anything. As a hint, the number is unbelievably huge.

Post edited by obsessedAndre on

## Replies to: The Hardest Math Problem Ever

34Registered User Junior Memberbut yeah there must be a huge number greater than 3.05 that satisfies that equation, 'cept i have noo clue how to find it xD..

maybe there's a geometric sequence with the amount each value's increase is decreasing x__o if that makes anY sense..!

240Registered User Junior Member248Registered User Junior Member3,164Registered User Senior Member240Registered User Junior MemberJust in case anyone's panicking, this is way beyond anything on the SAT or SAT II.

777Registered User Memberln(5 X 10^15) = 36.14821...

(5 X 10^15)^.1 = 37.1447...

every number higher than that works too so i guess thats prolly not right

240Registered User Junior MemberThe actual answer is n => 3.431 x 10^15, so you're answer is correct although it is not the smallest correct answer. You got the decimal places right, though!

What made you think of anything x 10^15? Did you just guess and check?

119Registered User Junior Member3,164Registered User Senior Member777Registered User Membersorry i couldnt be of more help...i have no idea how to do it...it had to be a huge number so after i tried like 10000 i did like 50 x 10^10 no, 50 x 10^15 yay :p. i didnt know you needed the smallest number possible though

1Registered User New Member9Registered User New Memberx>11ln0.1/1-(0.1)^11

1Registered User New Member72Registered User Junior Member2Registered User New Member3.028777595