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Old 10-20-2004, 03:42 PM   #1
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Join Date: Oct 2004
Posts: 1
hard problem... help please

Problem:
Three people leave identical coats in a checkroom. When the people check out, the 3 coats are distributed at random to the 3 people. Whats probability that none of the people recieve the correct coat.

plz respon asap. Thx
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Old 10-20-2004, 03:52 PM   #2
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Join Date: Oct 2004
Posts: 175
2/3* 1/2* 1/1= 1/3 You take the number of favorable outcomes over the total outcomes and multiply them together because the probabilities are dependant on one another. That explanation might not make sense but that is the right answer.
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Old 10-20-2004, 03:55 PM   #3
frs
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Join Date: Aug 2004
Posts: 171
Coats are labeled A, B, C

Persons: A B C

Coats: A B C
A C B
B A C
B C A
C A B
C B A

The only ones that don't match up to the top are BCA and CAB, 2 out of 6 combinations, so the probability is 1/3.

Yeah, uhh, this is the long way.
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