Sign Up For Free

**Join for FREE**,
and start talking with other members, weighing in on community discussions,
and more.

Also, by registering and logging in you'll see fewer ads and pesky welcome messages (like this one!)

- Reply to threads, and start your own.
- Post reviews of your campus visits.
- Find hundreds of pages of informative articles.
- Search from over 3 million scholarships.

College Confidential’s “Dean,” Sally Rubenstone, put together 25 of her best tips. So far, the "25 Tips from the Dean" eBook has helped more than 10K students choose a college, get in, and pay for it. Get your free copy: http://goo.gl/9zDJTM

Hyper2400
Registered User Posts: **770** Member

i could use the practice :)....let's see who can solve it the most efficiently...we can all learn from these efficient methods...

Post edited by Hyper2400 on

This discussion has been closed.

## Replies to: Math CHALLENGE...Post the hardest math SAT I questions you can find..

731Member(This can be, and is meant to be, solved geometrically, without trig. )

39Junior Member731Member175Junior Member238Junior Member39Junior MemberEDIT: Vehement answers works out for me.. did that the first time with my wrong isoceles.. but changed my method second time around =/ whoops

957Member957Memberok the full steps

first add up bde, ebc, ecb and ecd. you will get 160.

180 - 160 = angel a

180 - angel a(20)/2 = ade = 80

180 - dbe - dbc - bce = angel bdc = 30

subtract bdc(30) and ade(80) from 180 = the answer = 70

25,432Senior Member731Member2,529Super Moderatorthanks much!

957Member235Junior Member25,432Senior Member731Member