| Make sure to refer to the exact titlle of your book (White, second or third edition) or give the exact test date.
I assume that your questions are from the May 1997 test. If not, the joke is on me.
16. Be careful in checking all the INFORMATION that is given: Since x = y, you should notice that the triangles are isosceles right triangles. In this case, the booklet even gives us the formulas for a 45-45-90 triangle. The hypo is sqrt2*s and the two equal sides are s. Applying the formula yields:
BE = 4/square root2 (since 4 = sqrt2*BE)
CB = 8/square root2 (since 8 = sqrt2*CB).
Now add them to find CE which is 12/square root2. Multiply both sides by sqrt 2 and you obtain 12 square root2 /2 or 6 square root2. The answer is thus B.
17. Here you need to recognize that the opposite of half as fast as is ...twice as fast or double. Build a quick and dirty table starting from the bottom. Assign an easy value to 20. In this case, use the good old 1 and double each value:
20 = 1
15 = 2
10 = 4
5 = 8
So the answer is 8 to 1 or C.
23. First recognize that this problem is number 23 ... that means that you could spend a few seconds analyzing the figure. Resist plugging in figures to evaluate the rectangle -mostly because 2/3 is not a very natural number.
Look at the figure and draw an imaginary line that cuts the rectangle in two equal parts (horizontally). Now what did we get? A clear figure that shows that the "missing" part is a triangle worth 1/2 of the bottom rectangle or 1/4 of the entire rectangle. This means that the quadrilateral represents 3/4 of the rectangle. Now we can calculate ... 2/3 equals 3/4 x (x being the rectangle)
2/3 = 3/4 x
2/3 * 4/3 = x
8/9 = x
The answer is C.
Last edited by xiggi : 07-13-2005 at 08:08 PM.
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