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Old 07-14-2005, 01:25 PM   #1
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Join Date: May 2005
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10 real sat 2nd ed

p.607
19.how many 3 digit palindrome are there.

19
20
100
810
how did u find it
loganr is offline  
Old 07-14-2005, 01:47 PM   #2
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The first and third number are the same, and the second one can be anything.

The only constraint on the first/third number is that it cannot be equal to zero, or else it would not be a three digit number. So there are 9 possibilities (1 through 9).

There are no constraints on the second number. So there are 10 possibilities.

How many combinations are there? 9 x 10 = 90. The answer is C.
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Old 07-14-2005, 01:51 PM   #3
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You forgot to list THE answer that is 90.

How many numbers can be "in the middle" of three digits palindrome?
Everyone of 0 to 9 ... so that is 10 numbers.

How many can be on the sides?
O is not possible -it would become a single digit number-
That leaves us 9 combinations (1x1, 2x2, 3x3, etc.)

So the answer is 9 times 10 or 90.

PS This way you have 111, 121, 131, 141, all the way to 999.
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Old 07-14-2005, 04:15 PM   #5
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wow, i am soo lost. lol. What is a palindrome? and is that going to be on Sat I or SAT II?
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Old 07-14-2005, 04:17 PM   #6
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Quote:
What is a palindrome?
Your dictionary can answer the question for you. If you don't know how to use one, you're going to have definite problems with the SAT.
beginning is offline  
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