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maraudersmap
Posts: **14**Registered User New Member

Hey guys, I'm prepping for the Dec SAT and I think a daily math questions would help me improve. Can anyone help me with these questions? If you nee help too, feel free to post.

1. Kyle's lock combination consists of 3 two-digit numbers. The combination satisfies the three conditions below.

-One number is odd

-One number is a multiple of 5

-One number is the day of the month of Kyle's birthday

If each number satisfies exactly one of the conditions, which of the following could be the combination of the lock?

A. 14-20-13

B. 14-25-13

C. 15-18-16

D. 20-15-20

E. 34-30-21

I'm confused because A, B, and D all fit the conditions...

1. Kyle's lock combination consists of 3 two-digit numbers. The combination satisfies the three conditions below.

-One number is odd

-One number is a multiple of 5

-One number is the day of the month of Kyle's birthday

If each number satisfies exactly one of the conditions, which of the following could be the combination of the lock?

A. 14-20-13

B. 14-25-13

C. 15-18-16

D. 20-15-20

E. 34-30-21

I'm confused because A, B, and D all fit the conditions...

Post edited by maraudersmap on

## Replies to: Daily Math Questions

346Registered User MemberThe only thing you missed was the word "one." ONE number is odd. ONE number is a multiple of 5. And ONE number.. you get it.

A. 14-20-13

B. 14-25-13 - Eliminate because it has 2 odd numbers.

C. 15-18-16 - Eliminate because 15 can't satisfy two requirements.

D. 20-15-20 - Eliminate because it has two multiple of 5's.

E. 34-30-21 - Eliminate because 21 and 30 work, but 34 doesn't satisfy the birthday requirement.

A!

14Registered User New MemberHere's another one I need help with:

Let x be defined as [x]=x^2-x for all values of x. If [a]=a-2, what is the value of a?

A. 1

B. 1/2

C. 3/2

D. 6/5

E. 3

2,118Registered User Senior MemberQ: If p and q are positive integers such that pq = 50, which of the following cannot equal (p^2)q?

A: 50

B: 100

C: 200

D: 250

E: 500

2,118Registered User Senior Member[a] = a^2 - a = a - 2

a^2 - 2a + 2 = 0

a = (2 +- sqrt(4 - 8))/2, i.e. two complex solutions.

43Registered User Junior Member14Registered User New Member2,118Registered User Senior Member14Registered User New Member2,118Registered User Senior Membera^2 - a = (a-2)^2 - (a-2)

a^2 - a = a^2 - 5a + 6 (upon expanding, simplifying). a^2 cancels, leaving

-a = -5a + 6 --> a = 3/2

14Registered User New Member91Registered User Junior Member2,118Registered User Senior Member62Registered User Junior Member2,118Registered User Senior Member200 is 50*4, and 4 is not a factor of 50, so C is the answer.

3,449Registered User Senior Member