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11-17-2012, 01:51 PM
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#16 | | Junior Member
Join Date: Feb 2011
Posts: 199
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Bad test . Wasn't this overall easier than most test tho !
And who remembers more math q s ?
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11-17-2012, 01:52 PM
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#17 | | Junior Member
Join Date: May 2012
Posts: 103
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Adeetz thank you so much! That was the only vocab I wasnt sure of.
aimforthesky I thought the CR was harder than usual, writing was easy, and math was medium lolz.
haha Adeetz right on
Ive taken the 25 college board tests that are out there and thought this one was moderate compared to the others.
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11-17-2012, 01:53 PM
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#18 | | Senior Member
Join Date: Jul 2012
Posts: 1,791
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i hope they give a generous curve for CR... omg im really worried. and last time i already have a 430... T_T
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11-17-2012, 02:00 PM
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#19 | | Junior Member
Join Date: Feb 2011
Posts: 199
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My last score was a 2050 0_0 hoping for 2200 +
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11-17-2012, 02:08 PM
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#20 | | Junior Member
Join Date: May 2012
Posts: 103
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haha same!! I took it as a 10th grader and got a 2030, and Im hoping for a 2250+ now. I took all 25 practice tests out there. Have you heard that they flag your test for review if you jump more than 300 points?
I heard somewhere that the curve is gonna be harsh becuase this test is only for NY where ppl are like ubber smart compared to other places. I hope the collegeboard acknowledges this and alters the curve appropriately, cuz that would be so ridiculously unfair if they curved according to the NYC area. Also, this test is the end of seniors who have studying a lot and beginning of the smarter 11th graders, so the curve is already harsh.
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11-17-2012, 02:10 PM
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#21 | | Junior Member
Join Date: May 2012
Posts: 132
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I honestly don't know why everyone claims it is non-zero for the p prime question. Here's how I answered the question:
For what values does p* = (100p)*,
where a* = sum of prime factors of a
For any prime number, the only divisor is itself and one.
This implies that the sum of prime factors of a prime p is simply p.
100p = 2^2*5^2*p
Therefore, (100p)* is the sum of all prime factors of 100p, which are: 2, 5, p.
Thus, RHS(Right-hand-side) equals 2 + 5 + p.
LHS(Left-hand-side) equals p, as established above
p = 2 + 5 + p
0 = 7,
which is obviously always false, thus for no prime value, p does this equation have a solution.
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11-17-2012, 02:16 PM
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#22 | | Junior Member
Join Date: Jul 2012
Posts: 40
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What did you guys put for the #14 on secton 10 writing?
It was something like "Chris gardner.. each of them were hoping to become stockbrokers" or something like that
I put Each of them was hoping to become a stockbrocker but i think i'm wrong..
I picked choice (E)
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11-17-2012, 02:17 PM
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#23 | | Junior Member
Join Date: May 2012
Posts: 132
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^Magnetic, that is definitely correct.
Each is a singular noun, thus it is "was" not "were".
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11-17-2012, 02:23 PM
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#24 | | New Member
Join Date: Sep 2011
Posts: 3
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Was the lowest perimeter of the square question with side 4, 3, 2 and 1 - 24?
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11-17-2012, 02:25 PM
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#25 | | New Member
Join Date: Jul 2012
Posts: 16
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Insect I got that too.
If you want to check answers, go to the website like plum, browse through the standardized test section, and click on Nov 17 SAT Questions and Answers.
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11-17-2012, 02:29 PM
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#26 | | Junior Member
Join Date: Sep 2011
Posts: 50
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didn't it say the corners couldnt be touching? in that case the answer should be 28...
and also was the prime number question the experimental?
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11-17-2012, 02:31 PM
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#27 | | Junior Member
Join Date: Jul 2012
Posts: 40
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Awesome but what about the other writing question that was about the indian prime minister?
I picked the choice that began with "a diplomat" Choice (D) I think
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11-17-2012, 02:33 PM
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#28 | | Junior Member
Join Date: Sep 2012
Posts: 57
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did anyone get 862 for the question that asks for a 3 digit number whose digits have a product of 96?
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11-17-2012, 02:34 PM
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#29 | | Junior Member
Join Date: Sep 2012
Posts: 57
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also, I'm pretty sure the question with the 4x4, 3x3, 2x2 and 1x1 boxes only said there couldn't be overlap between the boxes; they could be adjacent in any manner. I got 24
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11-17-2012, 02:37 PM
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#30 | | Junior Member
Join Date: Jul 2012
Posts: 40
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@SoundsOfSilence that's correct
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