vadox6466

I need some help... How do you do this question:

pg 411 blue book, practise test 1, section 6, Q 13?

I can't type it up because it involves a graph, and it's a grid question. How the hell do you do it?

vadox6466

This one too, another grid one (blue book, pg 412, Q17):

"In the xy-coordinate plane, the graph of x = y^2 - 4 intersects line L at (0, p) and (5, t). What is the greatest possible value of slope L?"

vadox6466

Ah nevermind I found the updated thread..

Gyros321

If you mean question 13 then its simple.

Since H(x) = g(2x) + 2 then H(1) = G(2) + 2
G(2) on the graph is = to 1 (remember in G(X) the 2 is the X point so go that far on the x axis and you get a y point. That is where the 1 is coming from) and then add it to 2. There is your answer (3)

For question 2... it is also simple.
Ok first of all this is very simple. You have the point (0,p). Now find out what P is by plugging in 0 for X into the equation. You get + or - 2. NOw plug 5 in and you get + or - 3. Now think about it. To get the biggest slope you want to have a slope thats rising fast and running slow. ANd it has to be positive. So use the point (0, -2) and (5,3) for your 2 points of the slope.

You should get 5/5 for ur slope or 1.