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#7.
i don't know if there's a shorter way to do this, but here's what i did.
let t = number of days
for each day the net profit is [amount collected minus the cost] or (k - k/3), so the amount of days to reach $1000 is that quantity times the number of days. so our equation is
t(k - k/3) = 1000, and solve for t to find the number of days...
t(2k/3) = 1000
t=3000/2k
t=1500/k,
so the answer is D
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