| Ok, this is quite simple actually.
To state the obvious parts first:
x = amount of dollars 1st shirt
Since we have additional shirts, we have the x-z dollars.
x + (x-z)
Then, we know that n = amount of shirts
However, because of counting problems, we must place (n-1), in order to get the right [b]cost[b]. Therefore it must be:
x + (n-1)(x-z)
Think of it this way, if you are buying two shirts, you MUST put n-1, otherwise:
x + 2(x-z)
You would get the cost of 3 shirts. Remember that x represents the cost of the 1st shirt.
Hope that makes sense.
Last edited by Avex : 08-06-2007 at 11:11 AM.
|