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Ivan_Stanchev
Posts: **558**- Member

Let f(x)=x^2 - 5x +2 and g(x) = f(x-4)

Find the positive root of the equition f(x) = g(2)

I solved this ,the answer is 7, but do you thnik problem like this appears on the SAT ?It is from Barron`s 2400 club and is marked as ''hard'' In this book there are no 'easy' problems and the medium ones are the ones that we consider as ''hard'' on the real test.So this is supposed to be a ''superhard'' :}

Find the positive root of the equition f(x) = g(2)

I solved this ,the answer is 7, but do you thnik problem like this appears on the SAT ?It is from Barron`s 2400 club and is marked as ''hard'' In this book there are no 'easy' problems and the medium ones are the ones that we consider as ''hard'' on the real test.So this is supposed to be a ''superhard'' :}

Post edited by Ivan_Stanchev on

## Replies to: hard math problem

3,256Registered User Senior MemberI've seen problems like this and this is way above the level of an ETS question.

5,620Registered User Senior Member558- Member1,761Registered User Senior Member362Registered User Memberit's likely to show up as an easy level problem on the SAT II math, but for SAT I, it seems too straightforward and also because it wayyy too time consuming. I dont see how you could solve it in <30 seconds, which is the amount of time each math problem on SAT I is designed to take you...that is, if you do it the ETS way.

2,220Super Moderator Senior Memberg(2) = f(2-4)

g(2) = f(-2)

f(x) = f(-2)

Since x=2.5 is an axis of symmetry of parabola y=x^2-5x+2 (remember -b/2a)

f(7) = f(-2)

558- MemberBut you may spend 1.5 minutes for this type of questions and no more than 20 seconds f or each of the first 3 questions

1,761Registered User Senior Member558- Member1,761Registered User Senior Member