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Old 04-14-2011, 10:51 PM   #61
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Quote:
Where A is not equal to 1, (A^7-A^6)/(A-1)=?
A)a/(a-1)
B)1/(a-1)
C)A^6-A^5
D) A^5
E)A^6

The book says E, and I guessed A. How do you do this one?
Get a Ti-89!
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Old 06-18-2011, 10:57 PM   #62
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Heres a probability question.
There are 3 Republicans and 2 Democrats on a Senate committee. If a 3 person subcomittee is to be formed from this committee, what is the probability of selecting 2 Republicans and 1 Democrat?
I know that no. of ways to select 2 Rep. is 3, and that no. of ways to select 1 Dem. is 2 for 6 (3 x 2) possible ways. But how do you determine the total number of ways?(6/?)
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Old 06-19-2011, 07:50 PM   #63
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the total is 10 because is 5 C 3. so you get 10 since there are a total of five peopel for 3 spots.
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Old 06-22-2011, 08:17 PM   #64
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Quote:
Where A is not equal to 1, (A^7-A^6)/(A-1)=?
A)a/(a-1)
B)1/(a-1)
C)A^6-A^5
D) A^5
E)A^6

The book says E, and I guessed A. How do you do this one?
factor out A^6 from numerator: A^6(A-1)/(A-1)

then divide out (A-1)
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Old 06-22-2011, 09:01 PM   #65
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What is the least interger greater than 999 that is divisible by 6, 8, 9?

I was able to do this question fairly quickly by trial and error but was wandering if there is perhaps a mathematical and more direct approach. (maybe prime factorization)
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Old 06-24-2011, 06:18 PM   #66
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bump. anyone?
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Old 06-24-2011, 06:28 PM   #67
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Id just use trial/error. It works nearly 100% of the time and I don't feel like memorizing random facts and theorems
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Old 06-25-2011, 01:51 AM   #68
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Use prime factorization. 6 is 2*3, 8 is 2^3, and 9 is 3^2. The find the LCM, just choose the highest power of each factor. This gives you (2^3)*(3^2) = 8*9 = 72. Thus the number must be a multiple of 72. It is simple to see that the first multiple of 72 greater than 999 is 1008.
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Old 07-03-2011, 08:29 PM   #69
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difficult set question: a study of 400 fruit orchards showed that 250 of the orchards grew apples, 140 grew pears, 95 grew plums, 70 grew only apples and pears, 30 grew only apples and plums, 45 grew only pears and plums, and 10 grew all three.
18. how many of the orchards grew only apples or plums?
a) 30
b) 130
c) 150
d) 180
e) 345

19. How many of the orchards grew no apples, pears, or plums?
a) 0
b) 80
c) 165
d) 235
e) 320
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Old 07-03-2011, 09:17 PM   #70
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18. the answer is a
19. I think the answer should be 50 but I dont see it as a choice?

The easiest way to solve this is to make a venn diagram with three circles. Start with the last piece of information and work your way back while filling in your chart. I'm not sure why I'm not getting an answer choice for q 19. Maybe there is a mistake.
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Old 07-03-2011, 09:25 PM   #71
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whre did u get these problems from? is the first one D) 180 and the last one b) 80 .
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Old 07-03-2011, 09:31 PM   #72
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whre did u get these problems from? is the first one D) 180 and the last one b) 80 .
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Old 07-03-2011, 09:58 PM   #73
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nvr mind i think ezrahusney is right about the last one. i think it is 50 also.
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Old 07-03-2011, 10:35 PM   #74
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the first one should be 150 b/c u have to do (250-70-30-10) + (95-45-30)
apples + plums
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Old 07-03-2011, 10:38 PM   #75
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@ Arachnotron
this is related to GRE's question about rate and time. I figured out the rates but can you explain why you did this : (27sec/90ft)(100ft) = 30 seconds.?
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