sararabinovich

Thank you!

sararabinovich

Game Attendance
1 456
2 508
3 399
4 550
5 n
The table above shows the attendance at the home games of the Central High School football team. If the median attendance for the five games was 456, and no two games had the same attendance, what is the greatest possible value for n?

the choices are (A) 400
(B) 455
(c)457
(D)478
(E)549
I understand why thing answer is B and I get why none of the other answers make sense but why can't it be A?

RandomHSer

Putting the attendances in numerical order:
399,456,508,558 For the median to be 456, n has to be less than 456 ( and any number less than 456 will do). The question asks for the largest possible value of n. The largest integer (can't have fractional people at a game) less than 456 is 455, which is B.

rspence

@sararabinovich, questions's asking for the largest possible n. B) 455 definitely works, so A) is incorrect.

sararabinovich

Oh! I didn't realize it said largest. Haha I think the heat is getting to my head.

natyyyyym

Hiii!can you help me with this one please

http://i1069.photobucket.com/albums/...m/73ccbba0.jpg

rspence

17. The average rate is d(t)/t, or a + (1/2)bt. Right away, this eliminates choices B, D, and E because they are not in the form (constant) + (constant)t. Also, it cannot be A, otherwise d(t) = 0 + t^2, and 0 is not a positive constant. Therefore, process of elimination, D.

You can also show that D is right, since d(t) will equal t + t^2. It works for t=0, t=1, t=2, etc.

6thstation

Marbles are to be removed from a jar that contains 12 red marbles and 12 black marbles. What is the least number of marbles that could be removed so that the ratio of red marbles to black marbles left in the jar will be 4 to 3?




The answer is supposed to be 3..help?

pckeller

Remove 3 black marbles and the ratio will be 12:9 which reduces to 4:3. Were you thinking that the marbles would be moved to some other jar?

6thstation

sorry, heres another:

The interior dimensions of a rectangular fish tank are 4 feet long, 3 feet wide, and 2 feet high. The water level in the tank is 1 foot high. All of the water in this tank is poured into an empty second tank. If the interior dimensions of the second tank are 3 feet long, 2 feet wide, and 4 feet high, what is the height of the water in the second tank?

A) 0.5 ft
B) 1 ft
C) 1.5 ft
D) 2 ft
E) 4 ft

Answer: E

rspence

@6thstation it's D. One way to think of it is, the volumes of both tanks are equal (24 ft^3). The first tank is half full, so the second tank must also be half full upon dispensing the water into that tank. Half of 4 is 2, so the height of the water in the second tank is D) 2 ft.

pckeller

@rspence: that's a very nice explanation! Noticing that the volumes of the tanks are the same definitely leads to an easier solution...

rspence

@pckeller yeah it definitely helps to notice that the volumes are the same, but 6thstation claimed it was E. Is that his answer, or some error from a review book?

6thstation

I apologize; the answer was D.
Thank you!

charlesl15

In the equation, k and m are constants. If the equation is true for all values of x, what is the value of m?

(x-8)(x-k)= x^2-5kx+m

A is 8, B is 16, C is 24, D is 32, E is 40