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Arachnotron
Registered User Posts: **1,761** Senior Member

Give me any SAT Reasoning Test math question (or a question from a simulated practice test) and I'll post a solution. Specify detail (just the math work or explicit reasoning or w/e) if you want. I'll post ridiculously detailed solutions by default.

Post edited by Arachnotron on

## Replies to: Math help center

914Member#5 pg. 472 of Blue Book

#6 pg. 472 of BB

#8 pg. 473 of BB

2,604Senior Member1. http://img16.imageshack.us/img16/3329/q34g.jpg

2. http://img193.imageshack.us/img193/9058/78224058.jpg

3. http://img195.imageshack.us/img195/6129/52012792.jpg

Thanks.

1,761Senior MemberImage 1:

#15:

Since OD bisects <AOF, you know that m<AOD = m<DOF, and since you know that OC bisects <AOE, that m<AOB + m<BOC = m<COD + m<DOE, and since OB bisects <AOD, you know that m<BOC + m<COD = x = 40

Now since m<BOC + m<COD = 40, and since we know that OD bisects <AOF, we know that

40 + m<BOC + m<COD = 30 + m<DOE. Substituting, it is easy to see that the expression boils down to 40 + 40 = 30 + m<DOE, which gives that m<DOE is 50.

Finally, we want to find <BOE, which we can do by adding m<BOC + m<COD + m<DOE, which from the information we have derived simplifies to 40 + 50 =

90#17:

Since we remove every 4 inches, it is useful to find out how many triangles we will remove. This can be found by: 80/4 = 20. Then, notice that for every 1 inch you remove, you gain back 2 inches. So we gain back 20(2-1) = 20 inches, which would make our total length

100.1,761Senior Member#20

You know that the total rope length will be y + 4x, so the insight needed is an expression of y in terms of x. Luckily, we have area which gives xy = 4000. Now, rearranging, we see that x = 4000/y, which we can substitute into our expression to yield 16000/y, choice

B1,761Senior Member#7

Sum of the arc measures is 2pi or 360 degrees. It's divided into 5 equal segments. ABC gets two of these segments, which leaves 3 of these segments to AEC. Thus ratio of ABC to AEC is 2:3, choice

B.2,604Senior Member1,761Senior Member1,761Senior Member3,256Senior Member1,761Senior Member3,256Senior Member1,761Senior Member33Junior Member1,761Senior MemberTom's rate: 100 ft/27 sec

Bill's rate: 90 ft/27 sec.

(27sec/90ft)(100ft) = 30 seconds.

33Junior Memberfilling entries of an initially empty 2008