overachiever91

Depends on which section
BTW,there was that question that was like ''easy to control '' vs ''easy to be controlled'' ..

Martin_sage

Writing and Math were quite easy

Maroonita

can we discuss the answers? or has the embargo not been lifted yet?

abatis

Embargo has been lifted.
Embargo on the SAT Discussion lifted.

smartchap

how many minutes would it take to transfer blah blah blah from A to B?I got 160 minutes?

Bilguun

So, since the embargo has been lifted, let's get the discussion started.
Let's everyone write down questions we remember and answers to them.

So there was this stupid question with containers A and B, 900 and 200 gallons respectively. The answer was 160.

There was hair-growing question. The initial length of her hair was 5.

The last question of one of the math questions with "a" and "a+b". The answer was B.

11^3*25^3*49^3. The least prime was 5.

The question with two equilateral triangles. Find perimeters and find the difference. The answer was 6.

smartchap

The fn f(ab)=f(a) + f(b).I think the answer was 24.

Height of triangle=40/3.

Polygon question n(n-3)/2 was 65.

smartchap

The question which had the parabola ax²+b.It could only be -3.So, ONLY I.

rablinh

Yay, I agree with Bilguun, even though I do not remember the "a" and "a+b" question. Can you be specific about that?

There was f(x) -1 when we shift the graph 3 unit down, rite?

The question with p% and 2p<x<3p. The value of x can be 5/11, rite ?

smartchap

Volume of cuboid=144

Bilguun

The question with two triangles with common bases located on a line. The distance from the line to the point on a triangle was 40/3

The question with values. I think that both a and b were equal to 3x+7 so the answer was a=b.

The question with n(n-3)/2. The answer was 65.

The really easy question. x-2=1 what does x+2 equal? Answer was 5.

The answer with a line tangent to a circle. The arc had the length of one sixth of the circumference. The answer was 4*sqrt(3)

The question immediately before the grid-in part begins. It had a semi-colored circle and I think the area of the half of the circle was 8*pi. We had to find the diameter. Mine turned out to be 4*sqrt2

Adelina

what was the question about a and a+b?? I don't remember...

christineekim

anything u guys remember from the reading sections? Somehow I don't seem to remeber anything on them .. it was tough for sure

smartchap

x could be 150,becoz then the remaining angle would be 210,210/3=70.So,therefore,p=70...this perfectly satisfies the condition...140<150<210

Adelina

can the value of x be fraction?? because it is percentage...