nickel&dime

Hello, I couldn't find this problem anywhere else and the studyhall site had confusing page numbers.

10 Real Sat 3rd Edition
Sunday May 2000
Section 7, Question #4
pg. 592

[figure of square ABCD marked with diagonals BD and AC, which go through point P in the middle]

The figure above shows a square and five labeled points. What is the least number of these five points that need to be moved so that all five points lie on the same circle?

a) one
b) two
c) three
d) four
e) five

I don't understand the question--what kind of circle are they asking about? Does it have to be inscribed within the square? If there are no restrictions concerning the circle, I thought the answer could be anything, since you could just draw a big one over all the points and not have to move any at all.

Anyway, the book says the answer is (a).

nickel&dime

Bump. Please help!

cris2005

I think I know why that is, but not completely sure. You can draw a circle around any square. The points A,B,C,D are all on the same circle(I guess the word would be tangent). The only point you need to worry about is P. So the only point you need to move is P. Hence, the answer is A)1.

9999999tears

Please explain question 8, page 654 Official Guide to me. Thanks so much.

orange peel

What does 10RS mean?
What is consolidated?
And what books are these from?

P.s. what exactly is this thread for I dont get it?
pm me the answers plz. I cant get on often. even 1 answer is great