ticktock

does anyone remember the question: how many times does this function cross the x-axis? f(x)= xy^5-2x=3y+1 (or something like that?)

WantIvy

As for the imaginary numbers one, it was A (I think), whichever letter was the higher letter in the 2nd quadrant. Explaination:

On the real axis, the point was (-a,0) and on the imaginary axis, the point was (0,bi).
Thus, adding the points, you get -a+bi. (if that wasn't the question, sorry, since i don't remember it completely right now. i think that was the question though)

my question: the one with point P 6inches from plane M. How do you work that out? For some reason... complete blankage in my mind );

jcll2002

what do you think 6 omitted and 10 wrong is? I just want to see what an estimate (conservative for 10 wrong). That doesn't seem very good.

papakipari786

ditto i want to know to...i feel bad now

Nile

@duchess
good point, i read the axis wrong. I thought that was the visual representation of the data distribution...not a frequency chart. -_-;

"what do you think 6 omitted and 10 wrong is? I just want to see what an estimate (conservative for 10 wrong). That doesn't seem very good."

660~?

papakipari786

i have a strong feeling im going to end of retaking it i left a couple blank plus now it seems i got 2 wrong so far (the easy ones =[)
i was just really shaky for some reason
and ran out of time =[

jcll2002

Well i think i got under a 700 so ill just take it again in oct. oh well.

AP930

How does 4 omitted and 1 wrong look? I hope there weren't any stupid mistakes -_-.

koreajbpark

what will i get? i dont think i missed any but i omitted 10 ;;;;;;;
(did not put some of the answers on the answer document)

jcll2002

ap that looks like an 800

slshi

is the official book of sat subject tests from college board accurate in terms of determining the score? or does it vary a lot from year to year...cause you can omit up to 5 and still get an 800 according to it

AP930

TY, I pray I don't make careless errors...

kapwatt

You are a careless error...Lol just kidding, I am sure you were deliberately created.

Anyways, I am in the same situation as you AP currently. Are you taking the BC exam on Wednesday?

Did you put E: a = -3, c = -1
For which of the following has no real roots?

y = ax^2 + 3x + c was the equation. I am 100% sure it is E.
Actually I am not asking if it is E. I am just contributing to our pool.

Marathi power.

dean5150

kapwatt- I think I put A for that one. I think it was because a and c were positive, and b^2-4ac must be less than 0. so 9-4*a*c < 0. but if -3 and -1 was a choice, that would work too. ???

SunPenguin

well kapwatt, you're right. it is E i'm pretty sure. the trick of the question was to plug it into the quadratic formula, and E was the only one that gives you a negative value under the square root (I forgot what that part is called). so you have to end up factoring out a i, which makes the answer imaginary.