May 2008 MATH II - Page 7

agentunderfire38 · 05-03-2008, 02:02 PM

What did you guys get for the second question regading the shoulder length compared to the height. I believe the questions was what was the height of a person with shoulder length of 48 cm using the arithmetic mean. I put 191.9 i believe that was (D).

dean5150 · 05-03-2008, 02:03 PM

for the imaginary one, was point A the one with the same x value as one imaginary point and the same y value as the other?

azn4eyes00 · 05-03-2008, 02:03 PM

@ derek: im not sure if my answer was right. but i am pretty sure that one isnt a prime number...

dont they start
2,3,5,7,11...

Derek · 05-03-2008, 02:04 PM

azneyes: Um: Oh crap. Hahaha -_-

Ohh! the other one i omitted was the shoulder/height! thats right... i didnt know how to convert in to cm.
fudge.

some-dude · 05-03-2008, 02:06 PM

for the shoulder one...it was 190 something, but i dont remember what...i dont think i put D though.

wheel · 05-03-2008, 02:06 PM

oh crab. i don't think did the conversion into cm...

azn4eyes00 · 05-03-2008, 02:06 PM

u dont have to convert, everthing is proportional

solve for the average and u get that in w/h
set w/h = the shoulder width(given) / height (unknown)
solve the proportion
give u (IN CM) and the answer u get is also in CM

answer is 191 or something like that

dean5150 · 05-03-2008, 02:06 PM

I panicked when I saw cm too, but you don't need to convert because it's a ratio, right? I put 191.9 I think.

agentunderfire38 · 05-03-2008, 02:07 PM

Yah I just used the mean which was 0.25. Then solved for x using the equation 48/x = 0.25

some-dude · 05-03-2008, 02:07 PM

do you remember what the average proportion was....was it around like .251 ?

some-dude · 05-03-2008, 02:08 PM

man, i did everything right, but for some reason i remember putting B for that question..i hope i didnt get it wrong.

wheel · 05-03-2008, 02:09 PM

yeah. i belived the average proportion wsa .25 or something close to that number.

agentunderfire38 · 05-03-2008, 02:09 PM

Anyone know how to do the problem with f(-1)=1 where there is symmetry or a reflection across the line x=3 then it asked for f(-7).

mizami · 05-03-2008, 02:10 PM

isn't that still 1?

azn4eyes00 · 05-03-2008, 02:10 PM

the answer is negative one

its symmetric to x=3
both x=-1 and x=7 (it asked for f(7) not f(-7)) are 4 units away from this symmetrical line

thus their results should be identical...right?