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11-08-2009, 06:00 PM
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#316 | | New Member
Join Date: Nov 2009
Posts: 21
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so you guys think putting (0,0) for x-int was wrong? I went for the definition ( x-int is where it crosses the x-axis, with the value of y=0). It totally make sense to me
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11-08-2009, 06:07 PM
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#317 | | Senior Member
Join Date: Sep 2008
Posts: 1,483
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Did the question explicitly ask for whether it CROSSES?
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11-08-2009, 06:13 PM
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#318 | | Junior Member
Join Date: May 2009 Location: Miami, Florida
Posts: 127
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crosses and intersects are two different things.... i think it said "..will intersect the x-axis when..."
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11-08-2009, 06:16 PM
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#319 | | Senior Member
Join Date: Sep 2008
Posts: 1,483
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ok so the question is whether it says intersects or crosses
in the discussion in the first couple pages, I think most ppl used the word "intersect". Was it intersect?
also does anyone remember what the question for this "167.6" was?
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11-08-2009, 06:19 PM
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#320 | | New Member
Join Date: Nov 2009
Posts: 8
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Intersecting means having common point(s). That is clearly the case at (0, 0).
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11-08-2009, 06:20 PM
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#321 | | Senior Member
Join Date: Sep 2008
Posts: 1,483
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@nick
so the question asked for "intersect" and NOT crosses?
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11-08-2009, 06:22 PM
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#322 | | New Member
Join Date: Jul 2009
Posts: 4
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I think it said crosses
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11-08-2009, 06:23 PM
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#323 | | Junior Member
Join Date: Nov 2009
Posts: 76
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Yeah, it was definitely intersect, and therefore the answer was k<=0. End of discussion.
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11-08-2009, 06:31 PM
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#324 | | Senior Member
Join Date: Sep 2008
Posts: 1,483
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I personally remember it as intersect.
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11-08-2009, 07:03 PM
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#325 | | Junior Member
Join Date: Mar 2009
Posts: 122
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It was intersect, but even then, when you graph the equation and find points of intersection between X^2 and y=0, there are none. K<0
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11-08-2009, 07:09 PM
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#326 | | Junior Member
Join Date: Nov 2009
Posts: 76
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If you make x equal to zero, and k=0, then y=0 as well. You would have the line y=0, which is the x-axis, which intersects an infinite amount.
BTW: I graphed it, First Curve: y=x^2, Second Curve: y=0. Used 2nd - Calc - Intersect, found the intersection at (0,0). It intersects. If x=0 k has to be 0 to make y equal to 0.
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11-08-2009, 07:16 PM
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#327 | | Junior Member
Join Date: Mar 2009
Posts: 122
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@nigcruch I did the same but my calc is telling me error: no sign change, how did you get your result?
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11-08-2009, 07:21 PM
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#328 | | Senior Member
Join Date: Sep 2008
Posts: 1,483
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@andro
actually when u graph x^2 it does intersect
for the first curve, go 1 to the left of the y axis and for the second curve go one to the right of the y axis. For the guess, go to (0, 0). It does show the intersect
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11-08-2009, 07:24 PM
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#329 | | Junior Member
Join Date: Mar 2009
Posts: 122
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Oh ok I got it, damn it I got that one wrong.
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11-08-2009, 07:32 PM
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#330 | | Senior Member
Join Date: Sep 2008
Posts: 1,483
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ughhh Im so anxious to see how I did
does anyone remember what the question for this "167.6" was?
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