Welcome to College Confidential!

The leading college-bound community on the web

Sign Up For Free

Join for FREE, and start talking with other members, weighing in on community discussions, and more.

Also, by registering and logging in you'll see fewer ads and pesky welcome messages (like this one!)

As a CC member, you can:

  • Reply to threads, and start your own.
  • Post reviews of your campus visits.
  • Find hundreds of pages of informative articles.
  • Search from over 3 million scholarships.
Please take a moment to read our updated TOS, Privacy Policy, and Forum Rules.

The AP Chemistry Study Thread

shanianwangshanianwang Registered User Posts: 222 Junior Member
edited April 2008 in AP Tests Preparation
AP Chemers unite!

Which of the following dissolved would produce a slightly basic solution:

A) KNO3 B) FeCl3 C) KCN D) NH4Cl E) CH3NH3

For confused people: you answer the question, then pose your own question in the same post.
Post edited by shanianwang on

Replies to: The AP Chemistry Study Thread

  • sristisristi Registered User Posts: 847 Member
    I am going to say C) KCN.

    pretty sure as CN will form a weak acid with by snatching a hydrogen from water thus liberating some OH. The others except for E) are conjugate bases of strong acids so they wont do anything. I really cant explain anything about CH3NH3. can anyone help me with that?

    My question:
    A 22.0 gram sample of an unknown gas occupies 11.2 Liters at standard temperature and pressure. Which of the following could be the identity of the gas?
    A) CO2 (carbon dioxide)
    B) S03 (sulfite)
    C) O2 (oxygen gas)
    D) N2 (nitrogen gas)
    E) He (Helium)

    Good Luck !
  • stanfordreamstanfordream Registered User Posts: 143 Junior Member
    This was posted on another thread by Evilbooya:
    "you have solutions of AgNO3, Na2CO3, NaCl, and H2S in solutions of W,X,Y,and Z. using only test tubes and graduated cylinders, explain how you would determine which solution is what (no Ph paper allowed)"

    1. Add HCl: AgNO3 + HCl will form precipitate (AgCl); Na2CO3 will produce CO2 gas
    2. i'm not sure about H2S, but i think maybe if you add NaOH, you'll get SO2 gas.
    3. the one remaining must be NaCl

    Edit: to the above question. (A) CO2 22g/.5mol=44g/mol

    Why is water the most dense at 4 degrees C? (compared to its density at other temperatures)
  • smder99smder99 Registered User Posts: 802 Member
    something to do with IMF...not sure tho
    H-bonds or something go figure
  • theoneotheoneo Registered User Posts: 6,934 Senior Member
    Where's the question?!
  • youknowmeyouknowme Registered User Posts: 754 Member
    stanfordream, if you can only use test tubes and graduated cylinders, where did the HCl come from.
    My question:
    Mg(s) + NO3¯(aq) + H+(aq) --->Mg2+(aq) +NH4+(aq) + H2O(l)

    When the skeleton equation above is balanced and all coefficients reduced to their lowest whole-number terms. what is the coeficient for H+
  • EvilbooyaaEvilbooyaa Registered User Posts: 672 Member
    stan thanks for bringing my question to this thread, but unfortunately your answer is incorrect (you can't use HCl or NaOH, but something else is there if that's a hint for ya)

    the first one is KCN - CN- + H2O <--> HCN + OH-

    2nd one- PV = nRT T = 273, P = 1, V = 11.2
    n = 11.2/ (.0821*273)
    n = .5 mol.
    22g/.5mol = 44g MM = CO2.

    stan for yours, I actually have no idea. wow, nice question.

    you know me- damn redox..... gotta do this out on paper.
    Mg + NO3- --> Mg+2 + NH4+
    breaks down into
    Mg --> Mg+2 and NO3- --> NH4+
    Mg --> Mg+2 + 2e- = 4Mg --> 4Mg+2 + 8e-
    NO3- + 10H+ + 8e- --> NH4+ + 3H2O

    combine the two, the 8e- cancel
    4Mg + NO3- + 10H+ --> NH4+ + 3H2O + 4Mg+2

    coefficient for H+ is 10 assuming the solution is acidic.
  • stanfordreamstanfordream Registered User Posts: 143 Junior Member
    sorry, i miss intepreted the question. lemme try again
    X+Y yields precipitate and X+Z also yields precipitate; X+W has no precipitate. Thus, X is AgNO3, Y is either Na2CO3 or NaCl, and Z is the other. This leaves W as H2S.
    Now add H2S to both Y and Z. the one thats Na2CO3 will produce CO2. the one remaining is NaCl

    actually, about the question regarding water density, i have no idea why thats the case (its something about IMF) - i just know that it's 4 degrees C and have pondered about that for a while (did some book research and couldnt find a solid reasoning)

    now for a question,
    What is the electron configuration of Au?
  • mrniceguymrniceguy Registered User Posts: 302 Junior Member
    [Xe] 6s^2 4f^14 5d^9

    Q) Write a balanced equation for the dissociation of Iron(II) hydroxide (Ksp=8.0x10^-16). Then, calculate the molar solubility of Fe(OH)2.
  • theoneotheoneo Registered User Posts: 6,934 Senior Member
    Fe(OH)2 --> Fe2+ + 2OH-

    (x)(2x)^2 = 8.0e-16 --> 4x^3 = 8.0e-16 --> x = 5.8e-6


    What volume of dry carbon dioxide, measured at 25 degrees Celcius and 785 mm Hg, will result from the complete combustion of 2.50 g of pentane?
  • youknowmeyouknowme Registered User Posts: 754 Member
    mole of C5H12=2.5g/72(g/mole)
    mole of CO2=5*(2.5/72)
    V=nRT/P= 5*(2.5/72)*8.31*(25+273) / (785/760) = a number

    don't feel like to do the math. lol
  • CC AdminCC Admin Administrator Posts: 32,337 Senior Member
    I have a couple of questions

    1. Activation energy for an elementary process

    1) Is part of the net enthalpy change for the reaction
    2) None of these
    3) Is smaller for slower reactions and larger for faster reactions
    4) Is the energy required to produce the transition state from the reactants

    2. A reaction mechanism has several steps. The rate of the overall reaction is equal to

    1) the average rates of the steps
    2) the rate of the slowest step
    3) the rate of the fastest step
    4) the difference between the rate of the fastest step and the rate of the slowest step

    I put 3 for the first one and 2 for the second one. Can anyone verify?
  • CC AdminCC Admin Administrator Posts: 32,337 Senior Member
    1. Consider the multi-step reaction that has the overall reaction
    2A + 2B ---- C + D

    What is the rate law expression that would correspond to the following proposed mechanism?

    A + B <
    > I (fast)
    I + B
    > C + X (slow)
    X + A --- D (fast)

    1. Rate = k
    2. Rate = k [A]22
    3. Rate = k [A]
    4. Rate = k [A]2
    5. rate = k
    6. Rate = k [A]2
    7. Rate = k [A]
    8. Rate = k [A]2
    9. Rate = k[A]

    I put 5.

    2. The reaction 3A + 2B + 4C

    > products

    Is known to be second order in A, first order in B, and independent of the concentration of C. What is the value of the rate constant for this reaction if its rate is 0.695 M*s^-1 when [A] = 5.00 M, = 7.00 M, and [C] = 3.00 M?

    I got 0.00397 M^-2 s^-1

    3. For the reaction 2NO2 ----> 2NO + O2

    Rate = 1.4 * 10^-10 M*s [NO2]2 at 25.0 C.
    If 2 mol of NO2 are initially present in a sealed 1.00 liter vessel at 25 C, what is the concentration of NO2 after 140 years?

    I got 0.894 M.

    The decomposition of sulfuryl chloride into sulfur dioxide and chlorine

    SO2Cl2(g) ----> SO2(g) + Cl2(g)

    Follows first-order kinetics. At 320 C the rate constant is 2.2 * 10^-5 sec^-1. If one started with a sample containing 0.16 moles of sulfuryl chloride per liter at 320 C what concentration would be left after 6.00 hours?

    1) 0.10 M
    2) 0.15 M
    3) 0.052 M
    4) 0.12 M
    5) 0.26 M

    I put 1.

    Consider the reaction
    2NOCl (g)

    > 2 NO (g) + Cl2(g)

    With rate constant 0.0480 M^-1 s^-1 when conducted at 200 C. The initial concentration of NOCl was 0.521 M. What is the concentration of NOCl after 0.535 minutes and at 200 C?

    1. 0.289 M
    2. 0.0239 M
    3. 0.112 M
    4. 0.508 M
    5. 0.200 M

    I put 3 for this one.

    Can anyone verify these answers? Thanx.
  • celebrian25celebrian25 Registered User Posts: 15,373 Senior Member
    I have a question:

    how do I figure out the units of K for molecular collisions?
  • CC AdminCC Admin Administrator Posts: 32,337 Senior Member
    You take the rate and divide it by the concentration of the reactants.
  • stanfordreamstanfordream Registered User Posts: 143 Junior Member
    #3, i got 1.53M. here's how i did it,
    solve for k
    second order, so 1/x-1/2=kt
    solve for x, x=1.53M
    is that right?

    what is an activated complex?
This discussion has been closed.