# Welcome to College Confidential!

## The leading college-bound community on the web

Join for FREE, and start talking with other members, weighing in on community discussions, and more.

Also, by registering and logging in you'll see fewer ads and pesky welcome messages (like this one!)

### As a CC member, you can:

• Post reviews of your campus visits.
• Find hundreds of pages of informative articles.
• Search from over 3 million scholarships.

# Physics QUestion

Registered User Posts: 193 Junior Member
edited September 2007
A ship leaves its home port expecting to travel to a port 500 km due south. Before it can move, a severe storm comes up and blows the ship 100 km due east how far is the ship from its destination? In what direction must the ship travel to reach its destination?
Post edited by grantedin on

## Replies to: Physics QUestion

• Registered User Posts: 1,784 Member
Think of it on a graph. (distance formula)
• Registered User Posts: 193 Junior Member
I need to know the degree. When I made the graph I got about 79 degree. I do not know if it is correct of what it is relative to.
• Registered User Posts: 1,784 Member
You have a 90 degree angle at the origin. One leg is 100 km, the other is -500 km. You can figure out the rest with basic trig.
• Registered User Posts: 193 Junior Member
I understand what you are saying. Which angle should I solve for? I have to know the magnitude and the angle.
• Registered User Posts: 6,160 Senior Member
The angle the ship must travel to reach its target.
• Registered User Posts: 193 Junior Member
What is that angle relative to?
• Registered User Posts: 6,160 Senior Member
Imagine that the ship's position right after the storm, that is, (100,0), is the new starting point (aka, the new origin...0,0). Knowing that it must travel 100 km west and 500 km south, find the angle its path makes with the positive x-axis.
• Registered User Posts: 193 Junior Member
I still have a hard time doing this problem.
• Registered User Posts: 6,160 Senior Member
What level of math have you taken up to? It sounds like you haven't done trigonometry yet.
• Registered User Posts: 513 Member
The shortest distance it takes the ship to reach it's destination is the hypotenuse of a right triangle with legs of length 100 and 500. The answer is just sqrt(250000+10000). For the angle you want the angle between the 100km leg and the hypotenuse, so it's just arctan(500/100) southeast for the angle
• Registered User Posts: 193 Junior Member
Thank you very much!!!
• Registered User Posts: 4,318 Senior Member
Is that just a right triangle problem?
This discussion has been closed.