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grantedin
Registered User Posts: **193** Junior Member

Will you help me with #7 on page 10 from the link below?

http://lrt.ednet.ns.ca/corr_studies/pdf/sample_lessons/Grade_12/Physics_12.pdf

http://lrt.ednet.ns.ca/corr_studies/pdf/sample_lessons/Grade_12/Physics_12.pdf

Post edited by grantedin on

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## Replies to: Physics Question

1,068Senior MemberThere are 3 forces on the sign, gravity, A, and B. The sign will have to be in equilibrium so we want the the net force to be 0 and all the forces to balance out. Instead of using the 30 degree angle, instead use it's complement of 60. The y-component of the tension is just the weight. We know that Ty = T sin 60 so we can easily solve for the tension of A, 500sqrt3. Applying the Pythagorean theorem, we can solve for Tx, which is 433 N. This should also be the tension in B as well. So 433 N. If I'm wrong, hopefully someone can correct it.

513Member193Junior Member