Sign Up For Free

**Join for FREE**,
and start talking with other members, weighing in on community discussions,
and more.

Also, by registering and logging in you'll see fewer ads and pesky welcome messages (like this one!)

- Reply to threads, and start your own.
- Post reviews of your campus visits.
- Find hundreds of pages of informative articles.
- Search from over 3 million scholarships.

jai6638
Registered User Posts: **1,025** Member

Hey there..

I was given a question in a quiz for my Physics 1 class and I solved it. However, it was marked wrong. Could anyone please highlight why it is wrong?

Q) At a hockey game, you throw your hat into the air when our team scores a point. If you throw it upwards at an angle of 35 degrees with respect to the horizontal and speed of 11 m/s:

D) Assuming you are on level ground, how far away from you does it land ?

I found the time it takes to get to the highest point to be ( .6438 s and its maximum height to be .32 m ) in the earlier questions that I have not typed in this post.

To find this answer, I used the Range equation, R=((V0)^(2) * sin(2theta))/(g)

R= (11)^(2) * sin ( 2*35) / ( 9.8 )

R = 11.6 m.

Apparently, the answer is 5.8m but I'm not sure why it should be half of my answer. The range gives you the distance it covers in the X dimension so why is it half?!

Thanks

I was given a question in a quiz for my Physics 1 class and I solved it. However, it was marked wrong. Could anyone please highlight why it is wrong?

Q) At a hockey game, you throw your hat into the air when our team scores a point. If you throw it upwards at an angle of 35 degrees with respect to the horizontal and speed of 11 m/s:

D) Assuming you are on level ground, how far away from you does it land ?

I found the time it takes to get to the highest point to be ( .6438 s and its maximum height to be .32 m ) in the earlier questions that I have not typed in this post.

To find this answer, I used the Range equation, R=((V0)^(2) * sin(2theta))/(g)

R= (11)^(2) * sin ( 2*35) / ( 9.8 )

R = 11.6 m.

Apparently, the answer is 5.8m but I'm not sure why it should be half of my answer. The range gives you the distance it covers in the X dimension so why is it half?!

Thanks

Post edited by jai6638 on

This discussion has been closed.

## Replies to: Physics answer check

458Memberyou already figured it takes .6438s to reach its highest point,

so it takes 1.2876s total to fall down.

Vx=11*cos(35)

t=1.2876

X=Vx*t

=11*cos(35)*1.2876

=11.6

hmm.

4,706Senior Member458Memberif you assume that, it would travel even farther, not less.

jai6638/

it's not related to the current problem, but how did you get a maximum height of 0.32m? it should be 2.03m

t=0.6438s (time to get to the maximum height)

V_y0=11*sin(35)=6.31m/s

Y=V_y0*t-gt^2/2

=6.31*0.6438-(9.8)(.6438)^2/2

=2.03

=2.02m

...or maybe it's been too long since i've taken intro physics...

63Junior Member4,706Senior Member458MemberTherefore, your assumption does not help because it would make it go farther instead.

618Member53Junior MemberTaking this fact into consideration, the range of the hat is 5.8m.

139Junior Member4,706Senior Member618MemberWell, it does say, "assume you are on ground level."

63Junior MemberYour assumption would cause the object to travel further, not less, and is therefore not a suitable explanation. The explanation is, unless other info has been omitted, 11.6 m is correct, and TC should submit the problem for regrading.

618Member